Comprehensive Question Bank & Study Notes
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๐The absolute maximum value of a continuous function on a closed interval must occur at a critical point within the interval or at the endpoints of the interval.
We evaluate \(f(x)\) at \(x=1\), \(x=0\), and \(x=2\).At the critical point \(x=1\):\[f(1) = (1)^3 - 3(1) + 2 = 1 - 3 + 2 = \mathbf{0}\]At the left endpoint \(x=0\):\[f(0) = (0)^3 - 3(0) + 2 = 0 - 0 + 2 = \mathbf{2}\]At the right endpoint \(x=2\):\[f(2) = (2)^3 - 3(2) + 2 = 8 - 6 + 2 = \mathbf{4}\]
The largest value is 4.Therefore, the absolute maximum value of the function \(f(x) = x^3 - 3x + 2\) in the interval \([0, 2]\) is \(\mathbf{4}\).
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The rate at which the height of sugar inside the cylindrical tank increases can be determined using the formula for the volume of a cylinder:
\(V = \pi r^2 h\)
Given:
Since the radius remains constant, differentiate both sides of the volume equation with respect to time \(t\):
\(\dfrac{dV}{dt} = \pi r^2 \dfrac{dh}{dt}\)
Substitute the known values:
\(100\pi = \pi (10)^2 \dfrac{dh}{dt}\)
\(100\pi = 100\pi \dfrac{dh}{dt}\)
Dividing both sides by \(100\pi\):
\(\dfrac{dh}{dt} = 1 \text{ cm/s}\)
Therefore, the height of the sugar in the tank is increasing at a rate of \(1 \text{ cm/s}\).
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The derivative of \(f(x)\) with respect to \(x\) is:
\(f^{\prime }(x)=\cos x+\sin x-\lambda \)
For \(f(x)\) to be a decreasing function for all real values of \(x\), we must have:\(f^{\prime }(x)\le 0\)\(\cos x+\sin x-\lambda \le 0\) that is
\(\cos x+\sin x\le \lambda \)
Note that for an expression of the form \(a\cos x+b\sin x\), the maximum value is \(\sqrt{a^{2}+b^{2}}\).
Here, \(a=1\) and \(b=1\). So the maximum value of \(\cos x+\sin x\) is:\(\sqrt{1^{2}+1^{2}}=\sqrt{2}\)
Now the condition \(\cos x+\sin x\le \lambda \) for all real \(x\).implies that \(\lambda \) must be greater than or equal to the maximum possible value of \(\cos x+\sin x\).
Therefore, we must have:\(\lambda \ge \sqrt{2}\)
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Since the first derivative $f'(x)$ is strictly positive for all $x$, the function $f(x) = 2x + \cos x$ is an increasing function throughout its domain. This also rules out (A) and (B) because an increasing function has no local maxima or minima.
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A room freshner bottle in the shape of an inverted cone sprays the perfume at regular intervals such that volume of the perfume in the bottle decreases at the steady rate of 1 mm3/min. Find the rate at which level of perfume is dropping at an instant when level of perfume in the bottle is 10 mm, if the semi-vertical angle of conical bottle is $\frac{\pi}{6}$
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