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Let A be the event that the student buys a colouring book, and B be the event that the student buys a box of colours.
We are given: $P(A) = 0.7$ $P(B) = 0.2$ $P(A|B) = 0.3$
We know that $P(A|B) = \frac{P(A \cap B)}{P(B)}$. Therefore, $P(A \cap B) = P(A|B) \times P(B) = 0.3 \times 0.2 = 0.06$ So, the probability that the student buys both the colouring book and the box of colours is 0.06.
We need to find $P(B|A)$, which is the probability that the student buys a box of colours given that she buys the colouring book. $P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.7} = \frac{6}{70} = \frac{3}{35}$ So, the probability that the student buys a box of colours given that she buys the colouring book is $\frac{3}{35}$.
Final Answer: (i) 0.06, (ii) 3/35
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