The teacher hasn't uploaded a solution for this question yet.
A function is one-one if $f(x_1) = f(x_2)$ implies $x_1 = x_2$. Consider two distinct real numbers, for example, $x_1 = 1.2$ and $x_2 = 1.5$. Here, $f(1.2) = [1.2] = 1$ and $f(1.5) = [1.5] = 1$. Since $f(1.2) = f(1.5)$ but $1.2 \neq 1.5$, the function is not one-one.
A function is onto if the range equals the codomain. The codomain is given as $R$. However, the range of the greatest integer function $f(x) = [x]$ is the set of all integers, $Z$. Since $Z \subset R$ and $Z \neq R$, there exist elements in the codomain (e.g., $0.5$) that have no pre-image in the domain $R$ such that $[x] = 0.5$. Thus, the function is not onto.
Final Answer: The function is neither one-one nor onto.
AI generated content. Review strictly for academic accuracy.