Class NEET 2026 ALL Q #1951
KNOWLEDGE BASED
APPLY
4 Marks 2026 NTA-RE-NEET-2026 MCQ SINGLE
The green paramagnetic species formed by heating $KMnO_{4}$ at 513 K is
(A) $KO_{2}$
(B) $K_{2}MnO_{4}$
(C) $Mn_{3}O_{4}$
(D) $MnO$
Correct Answer: B

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Detailed Solution

Step 1: Analyze the reaction conditions

When potassium permanganate ($KMnO_{4}$) is heated to 513 K, it undergoes thermal decomposition. This is a standard inorganic chemistry reaction used to prepare potassium manganate.

Step 2: Write the balanced chemical equation

The decomposition reaction is represented as follows: $$2KMnO_{4} \xrightarrow{513 K} K_{2}MnO_{4} + MnO_{2} + O_{2}$$

Step 3: Identify the product properties

The product $K_{2}MnO_{4}$ (potassium manganate) is known to be green in color. Regarding its magnetic property, the manganese in $K_{2}MnO_{4}$ is in the +6 oxidation state ($MnO_{4}^{2-}$). The electronic configuration of $Mn^{6+}$ is $[Ar] 3d^{1}$, which contains one unpaired electron, making it paramagnetic.

Final Answer: K_{2}MnO_{4}

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Pedagogical Audit
Bloom's Analysis: This is an APPLY question because the student must recall specific chemical reactions and apply knowledge of electronic configurations to determine magnetic properties.
Knowledge Dimension: FACTUAL
Justification: The question tests specific knowledge of inorganic chemical properties and reaction products found in the NCERT textbook.
Syllabus Audit: In the context of NEET, this is classified as KNOWLEDGE. This question directly assesses the student's familiarity with the d-block elements chapter, specifically the preparation of oxoanions of manganese.