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Given: \((A+B)^{2}=A^{2}+B^{2}\)
Expanding the left side, we have: \((A+B)^{2} = (A+B)(A+B) = A^{2} + AB + BA + B^{2}\)
So, \(A^{2} + AB + BA + B^{2} = A^{2} + B^{2}\)
Subtracting \(A^{2}\) and \(B^{2}\) from both sides, we get: \(AB + BA = O\)
Therefore, \(AB = -BA\)
Correct Answer: \(AB = -BA\)<\/strong>
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