Class CBSE Class 12 Mathematics Differential Equations Q #659
KNOWLEDGE BASED
UNDERSTAND
1 Marks 2025 AISSCE(Board Exam) MCQ SINGLE
Which of the following is not a homogeneous function of \(x\) and \(y\) ?

(A) \(y^2 - xy\)
(B) \(x - 3y\)
(C) \(\sin^2 \frac{y}{x} + \frac{y}{x}\)
(D) \(\tan x - \sec y\)
Correct Answer: D
Explanation
A function $f(x, y)$ is said to be homogeneous of degree $k$ if $f(tx, ty) = t^k f(x, y)$ for some real number $k$ and all $t > 0$.

To identify a function that is not homogeneous, we look for functions where this scaling property does not hold. Common characteristics of non-homogeneous functions include:
1. **Presence of a constant term:** A term that does not involve $x$ or $y$.
2. **Terms with different total degrees:** For polynomial functions, if the sum of the powers of $x$ and $y$ in each term is not the same.
3. **Transcendental functions (e.g., exponential, logarithmic) that do not scale appropriately:** For instance, $e^x$, $\log(x+y)$, or $\sin(x)$ are generally not homogeneous unless their arguments are homogeneous of degree 0.

Let's consider a common example of a function that is not homogeneous:
The function $f(x, y) = x^2 + y + 1$ is not a homogeneous function.

**Step-by-step verification:**
1. **Recall the definition of a homogeneous function:** $f(tx, ty) = t^k f(x, y)$.
2. **Substitute $tx$ for $x$ and $ty$ for $y$ into the function $f(x, y) = x^2 + y + 1$:**
$$f(tx, ty) = (tx)^2 + (ty) + 1$$
3. **Simplify the expression:**
$$f(tx, ty) = t^2x^2 + ty + 1$$
4. **Compare $f(tx, ty)$ with $t^k f(x, y)$:**
If $f(x, y)$ were homogeneous, we should be able to factor out $t^k$ such that the remaining expression is $x^2 + y + 1$.
However, we cannot write $t^2x^2 + ty + 1$ as $t^k(x^2 + y + 1)$ for any constant $k$. For instance, the term $1$ does not scale with $t$, and the term $ty$ scales differently from $t^2x^2$.

Since $f(tx, ty) \ne t^k f(x, y)$ for any real number $k$, the function $f(x, y) = x^2 + y + 1$ is not a homogeneous function.

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Step-by-Step Solution

A homogeneous function of degree \(n\) is a function \(f(x, y)\) such that \(f(tx, ty) = t^n f(x, y)\) for some constant \(n\).

Let's analyze each option:

(A) \(f(x, y) = y^2 - xy\)
\(f(tx, ty) = (ty)^2 - (tx)(ty) = t^2y^2 - t^2xy = t^2(y^2 - xy) = t^2 f(x, y)\). This is homogeneous of degree 2.

(B) \(f(x, y) = x - 3y\)
\(f(tx, ty) = tx - 3ty = t(x - 3y) = t^1 f(x, y)\). This is homogeneous of degree 1.

(C) \(f(x, y) = \sin^2 \frac{y}{x} + \frac{y}{x}\)
\(f(tx, ty) = \sin^2 \frac{ty}{tx} + \frac{ty}{tx} = \sin^2 \frac{y}{x} + \frac{y}{x} = t^0 (\sin^2 \frac{y}{x} + \frac{y}{x})\). This is homogeneous of degree 0.

(D) \(f(x, y) = \tan x - \sec y\)
\(f(tx, ty) = \tan(tx) - \sec(ty)\). This cannot be written in the form \(t^n (\tan x - \sec y)\). Therefore, it is not a homogeneous function.

Correct Answer: \(\tan x - \sec y\)

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AI Suggestion: Option D

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Pedagogical Audit
Bloom's Analysis: This is an UNDERSTAND question because it requires students to comprehend the definition of a homogeneous function and apply that understanding to identify which of the given options does not fit the definition.
Knowledge Dimension: CONCEPTUAL
Justification: The question tests the understanding of the concept of homogeneous functions, rather than recalling specific facts or procedures.
Syllabus Audit: In the context of CBSE Class 12, this is classified as KNOWLEDGE. The question directly assesses the understanding of definitions and properties related to homogeneous functions, a topic covered in the textbook.