Class CBSE Class 12 Mathematics Applications of Integrals Q #1712
KNOWLEDGE BASED
APPLY
1 Marks 2026 AISSCE(Board Exam) MCQ SINGLE
The area of the region bounded by the curve $y=x$ and x-axis, between $x=0$ and $x=2$ is:
(A) 2 sq. units
(B) $\frac{1}{2}$ sq. unit
(C) 1 sq. unit
(D) 4 sq. units
Correct Answer: A

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Detailed Solution

Step 1: Identify the integral formula

The area $A$ of a region bounded by a curve $y = f(x)$, the x-axis, and the lines $x = a$ and $x = b$ is given by the definite integral: $$A = \int_{a}^{b} |f(x)| \, dx$$

Step 2: Set up the integral

Given the curve $y = x$, the limits $x = 0$ to $x = 2$, the area is: $$A = \int_{0}^{2} x \, dx$$

Step 3: Evaluate the integral

Using the power rule for integration $\int x^n \, dx = \frac{x^{n+1}}{n+1}$: $$A = \left[ \frac{x^2}{2} \right]_{0}^{2}$$ $$A = \left( \frac{2^2}{2} \right) - \left( \frac{0^2}{2} \right)$$ $$A = \frac{4}{2} - 0 = 2$$

Final Answer: 2 sq. units

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Pedagogical Audit
Bloom's Analysis: This is an APPLY question because the student must apply the fundamental theorem of calculus and the concept of definite integrals to calculate the area under a linear function.
Knowledge Dimension: PROCEDURAL
Justification: The question requires the execution of a standard mathematical algorithm (integration) to arrive at a specific numerical result.
Syllabus Audit: In the context of CBSE Class 12, this is classified as KNOWLEDGE. This question tests the foundational understanding of the 'Application of Integrals' chapter, specifically calculating the area under a simple curve.