If \(\begin{bmatrix}x+y&2\\ 5&xy\end{bmatrix}=\begin{bmatrix}6&2\\ 5&8\end{bmatrix},\) then the value of \((\frac{24}{x}+\frac{24}{y})\) is:

(i) Form the equations required to solve the problem of finding the price of each item, and express it in the matrix form $AX = B$. (ii) Find $|A|$ and confirm if it is possible to find $A^{-1}$. (iii) (a) Find $A^{-1}$, if possible, and write the formula to find $X$. OR (iii) (b) Find $A^2 - 8I$, where $I$ is an identity matrix.

If \(A\) and \(B\) are invertible matrices, then which of the following is not correct?

The value $|\begin{bmatrix}x+y & y+z & z+x\\ z & x & y\\ 1 & 1 & 1\end{bmatrix}|$ is :

If |(a, 3, 4), (1, 2, 1), (1, 4, 1)| = 0, then the value of a is