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A relation $R$ is reflexive if $(a, a) \in R$ for all $a \in A$. Here, $|a - a| = 0$, which is an even number. Since $0$ is not odd, $(a, a) \notin R$. Thus, $R$ is not reflexive.
A relation $R$ is symmetric if $(a, b) \in R \implies (b, a) \in R$. If $|a - b|$ is odd, then $|b - a| = |-(a - b)| = |a - b|$ is also odd. Thus, $R$ is symmetric.
A relation $R$ is transitive if $(a, b) \in R$ and $(b, c) \in R \implies (a, c) \in R$. Let $a=1, b=2, c=3$. Here, $|1-2|=1$ (odd) and $|2-3|=1$ (odd), so $(1, 2) \in R$ and $(2, 3) \in R$. However, $|1-3|=2$ (even), so $(1, 3) \notin R$. Thus, $R$ is not transitive.
Since the relation is not reflexive and not transitive, it is not an equivalence relation.
Final Answer: The relation R is not an equivalence relation.
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