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We know that for any real number $x$, the value of the cosine function lies in the interval $[-1, 1]$. Thus, $-1 \le \cos x \le 1$.
We need to find the range of $2 - \cos x$. Starting from $-1 \le \cos x \le 1$, we multiply by $-1$ to get $-1 \le -\cos x \le 1$. Adding $2$ to all parts, we get: $$2 - 1 \le 2 - \cos x \le 2 + 1$$ $$1 \le 2 - \cos x \le 3$$
Since $f(x) = \frac{1}{2 - \cos x}$, we take the reciprocal of the inequality. Taking the reciprocal reverses the inequality signs: $$\frac{1}{3} \le \frac{1}{2 - \cos x} \le \frac{1}{1}$$ Therefore, the range of $f(x)$ is $[\frac{1}{3}, 1]$.
Final Answer: [1/3, 1]
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