Oxidation of p-nitrotoluene with acidic $KMnO_{4}$ converts the methyl group into a carboxylic acid group, resulting in p-nitrobenzoic acid. The nitro group ($-NO_{2}$) is a strong electron-withdrawing group (EWG) due to both -I and -M effects. Since EWGs increase the acidity of benzoic acid by stabilizing the carboxylate anion, p-nitrobenzoic acid is indeed stronger than benzoic acid. Thus, Statement-I is correct.
Reduction of p-nitrotoluene with $Sn/HCl$ converts the nitro group into an amino group, resulting in p-toluidine (4-methylaniline). In p-toluidine, the methyl group ($-CH_{3}$) is an electron-donating group (EDG) due to the +I effect and hyperconjugation. EDGs increase the electron density on the nitrogen atom, making the lone pair more available for protonation compared to aniline. Therefore, p-toluidine is more basic than aniline. Thus, Statement-II is correct.
Final Answer: Both Statement-I and Statement-II are correct
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