Class NEET 2026 ALL Q #1938
COMPETENCY BASED
APPLY
4 Marks 2026 NTA-RE-NEET-2026 MCQ SINGLE
In a solar system, the time-period of revolution of a planet tracing a circular orbit of radius R is proportional to:
(A) $R^{3}$
(B) $R^{1/2}$
(C) $R^{3/2}$
(D) $R^{2}$
Correct Answer: C

AI Tutor Explanation

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Detailed Solution

Step 1: Identify the relevant physical law

According to Kepler's Third Law of Planetary Motion, the square of the time period of revolution ($T$) of a planet around the Sun is directly proportional to the cube of the semi-major axis ($R$) of its orbit.

Step 2: Formulate the mathematical relationship

The relationship is expressed as: $$T^2 \propto R^3$$

Step 3: Solve for T

To find the proportionality for the time period ($T$), we take the square root of both sides: $$T \propto (R^3)^{1/2}$$ $$T \propto R^{3/2}$$

Final Answer: R^{3/2}

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Pedagogical Audit
Bloom's Analysis: This is an APPLY question because the student must apply the known Kepler's Law to a specific circular orbit scenario to derive the relationship.
Knowledge Dimension: PROCEDURAL
Justification: The student is required to perform a mathematical manipulation of a physical law to arrive at the correct proportionality.
Syllabus Audit: In the context of NEET, this is classified as COMPETENCY. This question tests the fundamental understanding of Gravitation, a core unit in the NEET Physics syllabus, requiring quick recall and application of standard laws.