Class NEET 2026 ALL Q #1919
COMPETENCY BASED
APPLY
4 Marks 2026 NTA-RE-NEET-2026 MCQ SINGLE
An ideal gas is made of polyatomic molecules. Each of the molecules has three translational, three rotational and f number of vibrational modes. If the ratio of heat capacities $C_{P}/C_{V}$ of the gas is $8/7,$ then the value of f is:
(A) 1
(B) 4
(C) 3
(D) 2
Correct Answer: B

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Detailed Solution

Step 1: Identify Degrees of Freedom

For a polyatomic molecule, the total degrees of freedom ($f_{total}$) is the sum of translational, rotational, and vibrational modes. Given: translational = 3, rotational = 3, and vibrational = $f$. Each vibrational mode contributes 2 degrees of freedom (kinetic and potential energy). Thus, $f_{total} = 3 + 3 + 2f = 6 + 2f$.

Step 2: Relate Heat Capacities to Degrees of Freedom

The molar heat capacity at constant volume is given by $C_V = \frac{f_{total}}{2}R$. The molar heat capacity at constant pressure is $C_P = C_V + R = (\frac{f_{total}}{2} + 1)R$. The ratio $\gamma = \frac{C_P}{C_V} = 1 + \frac{2}{f_{total}}$.

Step 3: Solve for f

Given $\gamma = \frac{8}{7}$, we set up the equation: $$\frac{8}{7} = 1 + \frac{2}{6 + 2f}$$ $$\frac{1}{7} = \frac{2}{6 + 2f}$$ $$6 + 2f = 14$$ $$2f = 8$$ $$f = 4$$

Final Answer: 4

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Pedagogical Audit
Bloom's Analysis: This is an APPLY question because it requires the student to utilize the theoretical formula for degrees of freedom and the adiabatic index to solve for an unknown variable in a specific physical scenario.
Knowledge Dimension: PROCEDURAL
Justification: The student must follow a sequence of steps involving thermodynamic definitions and algebraic manipulation to reach the result.
Syllabus Audit: In the context of NEET, this is classified as COMPETENCY. This question tests the application of the Kinetic Theory of Gases and Thermodynamics, which is a core high-weightage topic in the NEET Physics syllabus.