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Let matrix $A$ represent the number of books sold on each day for each subject. $$A = \begin{bmatrix} 50 & 60 & 35 \\ 40 & 45 & 50 \end{bmatrix}$$ Here, rows represent Day I and Day II, and columns represent Chemistry, Physics, and Maths respectively.
Let matrix $B$ represent the selling price of each book. $$B = \begin{bmatrix} 150 \\ 175 \\ 180 \end{bmatrix}$$ Here, rows represent the selling price of Chemistry, Physics, and Maths books respectively.
To find the total sales for each day, we multiply matrix $A$ by matrix $B$. $$AB = \begin{bmatrix} 50 & 60 & 35 \\ 40 & 45 & 50 \end{bmatrix} \begin{bmatrix} 150 \\ 175 \\ 180 \end{bmatrix} = \begin{bmatrix} (50 \times 150) + (60 \times 175) + (35 \times 180) \\ (40 \times 150) + (45 \times 175) + (50 \times 180) \end{bmatrix}$$ $$AB = \begin{bmatrix} 7500 + 10500 + 6300 \\ 6000 + 7875 + 9000 \end{bmatrix} = \begin{bmatrix} 24300 \\ 22875 \end{bmatrix}$$ The total sale on Day I is ₹24,300 and on Day II is ₹22,875.
The total sale in two days is the sum of the sales on Day I and Day II. Total Sale = ₹24,300 + ₹22,875 = ₹47,175
The cost price of all books is ₹35,000. Profit = Total Sale - Cost Price Profit = ₹47,175 - ₹35,000 = ₹12,175
Final Answer: Total sale in two days is ₹47,175 and the profit is ₹12,175.
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