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Let $y = 2^{\cos^2 x}$. We need to find $\frac{dy}{d(\cos^2 x)}$.
Let $u = \cos^2 x$. Then $y = 2^u$. We want to find $\frac{dy}{du}$.
We know that the derivative of $a^x$ with respect to $x$ is $a^x \ln a$. Therefore, the derivative of $2^u$ with respect to $u$ is $2^u \ln 2$.
Substituting $u = \cos^2 x$ back into the expression, we get $\frac{dy}{du} = 2^{\cos^2 x} \ln 2$.
Final Answer: $2^{\cos^2 x} \ln 2$
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