Explanation
$i^{k_1} + i^{k_2} \ne 0 \Rightarrow i^{k_1} \rightarrow 4$ option for $i, -1, -i, 1$
Total cases $ \Rightarrow 4 \times 4 = 16$
Unfovourble cases $ \Rightarrow i^{k_1} + i^{k_2} = 0$
$ \{\begin{array}{c}1, -1 \\ -1, 1 \\ i, -i \\ -i, i\end{array}\}$
4 Cases $\Rightarrow$ Probability $ = \frac{16-4}{16} = \frac{3}{4}$