The teacher hasn't uploaded a solution for this question yet.
Question 1:
Given: $\vec{AC} = \frac{5}{4}\vec{AB}$
We know that $\vec{AC} = \vec{c} - \vec{a}$ and $\vec{AB} = \vec{b} - \vec{a}$
Substituting these into the given equation, we get: $\vec{c} - \vec{a} = \frac{5}{4}(\vec{b} - \vec{a})$
Multiplying out the right side: $\vec{c} - \vec{a} = \frac{5}{4}\vec{b} - \frac{5}{4}\vec{a}$
Isolating $\vec{c}$: $\vec{c} = \vec{a} + \frac{5}{4}\vec{b} - \frac{5}{4}\vec{a}$
Combining terms: $\vec{c} = -\frac{1}{4}\vec{a} + \frac{5}{4}\vec{b}$
Question 2:
The direction ratios of the first line are (2, 7, -3).
The direction ratios of the second line are (-1, 2, 4).
For the lines to be perpendicular, the dot product of their direction ratios must be zero.
So, (2)(-1) + (7)(2) + (-3)(4) = -2 + 14 - 12 = 0.
Since the dot product is zero, the lines are perpendicular to each other.
Correct Answer: Question 1: $\vec{c} = -\frac{1}{4}\vec{a} + \frac{5}{4}\vec{b}$ , Question 2: Yes, the lines are perpendicular.
AI generated content. Review strictly for academic accuracy.