Class CBSE Class 12 Mathematics Integrals Q #628
KNOWLEDGE BASED
APPLY
1 Marks 2025 AISSCE(Board Exam) MCQ SINGLE
\(\int_{-1}^{1} \frac{|x|}{x} \, dx, x \ne 0 \text{ is equal to}\)
(A) \(-1\)
(B) 0
(C) 1
(D) 2
Correct Answer: B

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Step-by-Step Solution

**Step 1: Understand the absolute value function** The absolute value function is defined as: \[ |x| = \begin{cases} -x, & \text{if } x < 0 \\ x, & \text{if } x \ge 0 \end{cases} \]
**Step 2: Rewrite the integral using the definition of |x|** Since the integral is from -1 to 1, we need to split the integral at x = 0: \[ \int_{-1}^{1} \frac{|x|}{x} \, dx = \int_{-1}^{0} \frac{|x|}{x} \, dx + \int_{0}^{1} \frac{|x|}{x} \, dx \] For \(x < 0\), \(|x| = -x\), and for \(x > 0\), \(|x| = x\). Therefore: \[ \int_{-1}^{0} \frac{-x}{x} \, dx + \int_{0}^{1} \frac{x}{x} \, dx = \int_{-1}^{0} -1 \, dx + \int_{0}^{1} 1 \, dx \]
**Step 3: Evaluate the integrals** \[ \int_{-1}^{0} -1 \, dx = -x \Big|_{-1}^{0} = -(0 - (-1)) = -1 \] \[ \int_{0}^{1} 1 \, dx = x \Big|_{0}^{1} = (1 - 0) = 1 \]
**Step 4: Add the results** \[ -1 + 1 = 0 \]

Correct Answer: 0

AI Suggestion: Option B

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Pedagogical Audit
Bloom's Analysis: This is an APPLY question because the student needs to apply the definition of the absolute value function and then integrate.
Knowledge Dimension: PROCEDURAL
Justification: The question requires the student to follow a procedure to solve the integral, including splitting the integral based on the absolute value function's definition and then applying integration rules.
Syllabus Audit: In the context of CBSE Class 12, this is classified as KNOWLEDGE. The question directly tests the student's knowledge of integration and the properties of absolute value functions, which are covered in the textbook.