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We are given that |adj A| = 64, where A is a 3x3 matrix.
We know that for a square matrix A of order n, |adj A| = |A|^(n-1).
In this case, n = 3, so |adj A| = |A|^(3-1) = |A|^2.
Therefore, |A|^2 = 64.
Taking the square root of both sides, we get |A| = ±√64 = ±8.
So, |A| = 8 or |A| = -8.
Correct Answer: 8 or -8
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