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We are given that $A^2 = A$. We need to find the value of $(I+A)^2 - 3A$.
First, expand $(I+A)^2$:
$(I+A)^2 = (I+A)(I+A) = I^2 + IA + AI + A^2 = I + A + A + A^2 = I + 2A + A^2$
Since $A^2 = A$, we can substitute this into the expression:
$(I+A)^2 = I + 2A + A = I + 3A$
Now, substitute this back into the original expression:
$(I+A)^2 - 3A = (I + 3A) - 3A = I + 3A - 3A = I$
Therefore, $(I+A)^2 - 3A = I$.
Correct Answer: I
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