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Given: A = \begin{bmatrix}3&4\\ 5&2\end{bmatrix} and 2A + B = 0 (null matrix)
First, calculate 2A:
2A = 2 * \begin{bmatrix}3&4\\ 5&2\end{bmatrix} = \begin{bmatrix}6&8\\ 10&4\end{bmatrix}
Since 2A + B = 0, we can write B = -2A
Therefore, B = - \begin{bmatrix}6&8\\ 10&4\end{bmatrix} = \begin{bmatrix}-6&-8\\ -10&-4\end{bmatrix}
Correct Answer: \begin{bmatrix}-6&-8\\ -10&-4\end{bmatrix}
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