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Let the order of matrix A be \(n \times m\). This is given.
Let the order of matrix B be \(p \times q\).
For \(AB'\) to be defined, the number of columns of A must be equal to the number of rows of \(B'\). Since B is \(p \times q\), \(B'\) is \(q \times p\). Therefore, \(m = q\).
For \(B'A\) to be defined, the number of columns of \(B'\) must be equal to the number of rows of A. Therefore, \(p = n\).
So, the order of B is \(p \times q = n \times m\).
Correct Answer: \(n\times m\)
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