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We perform matrix multiplication of Q and P: $$QP = \begin{bmatrix}2&2&-4\\-4&2&-4\\2&-1&5\end{bmatrix} \begin{bmatrix}1&-1&0\\2&3&4\\0&1&2\end{bmatrix}$$ Calculating each element: Row 1: (2*1+2*2-4*0)=6, (2*-1+2*3-4*1)=0, (2*0+2*4-4*2)=0 Row 2: (-4*1+2*2-4*0)=0, (-4*-1+2*3-4*1)=6, (-4*0+2*4-4*2)=0 Row 3: (2*1-1*2+5*0)=0, (2*-1-1*3+5*1)=0, (2*0-1*4+5*2)=6 Thus, $$QP = 6I$$, where I is the identity matrix.
The system is $PX = B$, where: $$P = \begin{bmatrix}1&-1&0\\2&3&4\\0&1&2\end{bmatrix}, X = \begin{bmatrix}x\\y\\z\end{bmatrix}, B = \begin{bmatrix}3\\17\\7\end{bmatrix}$$
Since $$QP = 6I$$, we have $$P^{-1} = \frac{1}{6}Q$$. $$X = P^{-1}B = \frac{1}{6}Q B$$ $$X = \frac{1}{6} \begin{bmatrix}2&2&-4\\-4&2&-4\\2&-1&5\end{bmatrix} \begin{bmatrix}3\\17\\7\end{bmatrix}$$ $$X = \frac{1}{6} \begin{bmatrix}6+34-28\\-12+34-28\\6-17+35\end{bmatrix} = \frac{1}{6} \begin{bmatrix}12\\-6\\24\end{bmatrix} = \begin{bmatrix}2\\-1\\4\end{bmatrix}$$
Final Answer: x=2, y=-1, z=4
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