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Given the matrix equation:
\[\begin{bmatrix}x+y&2\\ 5&xy\end{bmatrix}=\begin{bmatrix}6&2\\ 5&8\end{bmatrix}\]From the equality of matrices, we have two equations:
We need to find the value of \(\frac{24}{x} + \frac{24}{y}\). We can rewrite this expression as:
\[\frac{24}{x} + \frac{24}{y} = 24\left(\frac{1}{x} + \frac{1}{y}\right) = 24\left(\frac{x+y}{xy}\right)\]Now, substitute the values of \(x+y\) and \(xy\) from the equations above:
\[24\left(\frac{6}{8}\right) = 24\left(\frac{3}{4}\right) = 6 \times 3 = 18\]Correct Answer: 18
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