1. Find the velocity function by differentiating the displacement function with respect to time:
x(t) = t^3 - 6t^2 + 3t + 4
v(t) = dx/dt = 3t^2 - 12t + 3
2. Find the acceleration function by differentiating the velocity function with respect to time:
a(t) = dv/dt = 6t - 12
3. Set the acceleration to zero and solve for time t:
6t - 12 = 0
6t = 12
t = 2
4. Substitute the value of t back into the velocity function to find the velocity when acceleration is zero:
v(2) = 3(2)^2 - 12(2) + 3
v(2) = 3(4) - 24 + 3
v(2) = 12 - 24 + 3
v(2) = -9
Correct Answer: -9
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