Given the differential equation: \(x~dy + y~dx = 0\)
Rearrange the equation: \(x~dy = -y~dx\)
Separate the variables: \(\frac{dy}{y} = -\frac{dx}{x}\)
Integrate both sides: \(\int \frac{dy}{y} = -\int \frac{dx}{x}\)
Evaluate the integrals: \(log|y| = -log|x| + c'\), where \(c'\) is the constant of integration.
Rewrite the equation: \(log|y| + log|x| = c'\)
Combine the logarithms: \(log|xy| = c'\)
Remove the logarithm by exponentiating: \(|xy| = e^{c'}\)
Let \(c = e^{c'}\), where \(c\) is another constant. Then \(xy = c\)
Correct Answer: \(xy=c\)
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