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Step-by-Step Solution
Given \((\vec{a}-\vec{b})\cdot(\vec{a}+\vec{b})=512\).
Expanding the dot product, we get \(|\vec{a}|^2 - |\vec{b}|^2 = 512\).
Also, given \(|\vec{a}|=3|\vec{b}|\).
Substituting \(|\vec{a}|=3|\vec{b}|\) into the first equation, we get \((3|\vec{b}|)^2 - |\vec{b}|^2 = 512\).
This simplifies to \(9|\vec{b}|^2 - |\vec{b}|^2 = 512\), which means \(8|\vec{b}|^2 = 512\).
Dividing both sides by 8, we get \(|\vec{b}|^2 = 64\).
Taking the square root, we find \(|\vec{b}| = 8\).
Since \(|\vec{a}|=3|\vec{b}|\), we have \(|\vec{a}| = 3 \times 8 = 24\).
Therefore, the respective values of \(|\vec{a}|\) and \(|\vec{b}|\) are 24 and 8.
Correct Answer: 24 and 8
AI Suggestion: Option C
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Pedagogical Audit
Bloom's Analysis:
This is an APPLY question because it requires students to apply their knowledge of dot products and vector magnitudes to solve for the unknown magnitudes.
Knowledge Dimension:PROCEDURAL
Justification:The question requires the student to follow a specific procedure to solve the problem, involving algebraic manipulation and substitution.
Syllabus Audit:
In the context of CBSE Class 12, this is classified as COMPETENCY. It assesses the student's ability to apply vector algebra concepts to solve a problem, rather than just recalling definitions or theorems.