Class CBSE Class 12 Mathematics Vector Algebra Q #551
COMPETENCY BASED
APPLY
1 Marks 2024 AISSCE(Board Exam) MCQ SINGLE
The position vectors of points P and Q are \(\vec{p}\) and \(\vec{q}\) respectively. The point R divides line segment PQ in the ratio 3:1 and S is the mid-point of line segment PR. The position vector of S is:
(A) \(\frac{\vec{p}+3\vec{q}}{4}\)
(B) \(\frac{\vec{p}+3\vec{q}}{8}\)
(C) \(\frac{5\vec{p}+3\vec{q}}{4}\)
(D) \(\frac{5\vec{p}+3\vec{q}}{8}\)
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AI Tutor Explanation

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Step-by-Step Solution

Step 1: Find the position vector of point R.

Since R divides PQ in the ratio 3:1, we can use the section formula to find the position vector of R (\(\vec{r}\)):

\(\vec{r} = \frac{3\vec{q} + 1\vec{p}}{3+1} = \frac{3\vec{q} + \vec{p}}{4}\)

Step 2: Find the position vector of point S.

Since S is the midpoint of PR, we can find the position vector of S (\(\vec{s}\)) using the midpoint formula:

\(\vec{s} = \frac{\vec{p} + \vec{r}}{2}\)

Step 3: Substitute the value of \(\vec{r}\) into the equation for \(\vec{s}\).

\(\vec{s} = \frac{\vec{p} + \frac{3\vec{q} + \vec{p}}{4}}{2}\)

Step 4: Simplify the expression for \(\vec{s}\).

\(\vec{s} = \frac{\frac{4\vec{p} + 3\vec{q} + \vec{p}}{4}}{2} = \frac{5\vec{p} + 3\vec{q}}{8}\)

Correct Answer: \(\frac{5\vec{p}+3\vec{q}}{8}\)

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Pedagogical Audit
Bloom's Analysis: This is an APPLY question because the student needs to apply the section formula and midpoint formula to find the position vector of point S.
Knowledge Dimension: PROCEDURAL
Justification: The question requires the student to apply specific algorithms (section formula and midpoint formula) to solve the problem.
Syllabus Audit: In the context of CBSE Class 12, this is classified as COMPETENCY. The question assesses the student's ability to apply the concepts of vectors and section formula in a problem-solving context.