A matrix $A$ is symmetric if and only if $A = A^T$, which implies that the element at row $i$ and column $j$ must be equal to the element at row $j$ and column $i$ for all $i, j$. Mathematically, $a_{ij} = a_{ji}$.
Given $A = \begin{bmatrix} 1 & a & b \\ -1 & 2 & c \\ 0 & 5 & 3 \end{bmatrix}$. Comparing $a_{ij}$ with $a_{ji}$:
For $i=1, j=2$: $a_{12} = a_{21} \implies a = -1$.
For $i=1, j=3$: $a_{13} = a_{31} \implies b = 0$.
For $i=2, j=3$: $a_{23} = a_{32} \implies c = 5$.
Substitute the values $a = -1$, $b = 0$, and $c = 5$ into the expression $3a + b + c$:
$$3(-1) + 0 + 5$$ $$-3 + 0 + 5 = 2$$Final Answer: 2
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