For any non-singular square matrix A of order n and a non-zero scalar k, the property of the inverse of a product is given by (kA)-1 = k-1A-1.
In the given expression (3A)-1, the scalar k is 3. Applying the property:
$$ (3A)^{-1} = 3^{-1} A^{-1} $$Since 3-1 = 1/3, we substitute this back into the expression:
$$ (3A)^{-1} = \frac{1}{3} A^{-1} $$Final Answer: $\frac{1}{3}A^{-1}$
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