The teacher hasn't uploaded a solution for this question yet.
Let $D$ be the event that a debate competition is held, and $Q$ be the event that a quiz competition is held. Given: $P(D) = \frac{1}{3}$ and $P(Q) = \frac{2}{3}$.
Team A has 4 girls and 6 boys (Total 10). The probability of selecting 1 girl and 1 boy from Team A is: $$P(E|D) = \frac{\binom{4}{1} \times \binom{6}{1}}{\binom{10}{2}} = \frac{4 \times 6}{45} = \frac{24}{45} = \frac{8}{15}$$
Team B has 7 girls and 3 boys (Total 10). The probability of selecting 1 girl and 1 boy from Team B is: $$P(E|Q) = \frac{\binom{7}{1} \times \binom{3}{1}}{\binom{10}{2}} = \frac{7 \times 3}{45} = \frac{21}{45} = \frac{7}{15}$$
The total probability $P(E)$ is given by: $$P(E) = P(D) \times P(E|D) + P(Q) \times P(E|Q)$$ $$P(E) = \left(\frac{1}{3} \times \frac{8}{15}\right) + \left(\frac{2}{3} \times \frac{7}{15}\right)$$ $$P(E) = \frac{8}{45} + \frac{14}{45} = \frac{22}{45}$$
Final Answer: 22/45
AI generated content. Review strictly for academic accuracy.