The conditional probability of an event $A'$ given $B'$ is defined as: $$P(A'/B') = \frac{P(A' \cap B')}{P(B')}$$
According to De Morgan's Law, the intersection of the complements of two sets is the complement of their union: $$A' \cap B' = (A \cup B)'$$ Therefore, $P(A' \cap B') = P((A \cup B)') = 1 - P(A \cup B)$.
Substitute the result from Step 2 into the formula from Step 1: $$P(A'/B') = \frac{1 - P(A \cup B)}{P(B')}$$
Final Answer: D
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