Class CBSE Class 12 Mathematics Probability Q #1411
KNOWLEDGE BASED
APPLY
3 Marks 2025 AISSCE(Board Exam) SA
Find the probability distribution of the number of boys in families having three children, assuming equal probability for a boy and a girl.

AI Tutor Explanation

Powered by Gemini

Detailed Solution

Step 1: Define the Random Variable

Let $X$ be the random variable representing the number of boys in a family with three children. The possible values of $X$ are 0, 1, 2, and 3.

Step 2: List Possible Outcomes

The sample space for the genders of three children is: {BBB, BBG, BGB, GBB, GGB, GBG, BGG, GGG}. Since the probability of having a boy or a girl is equal (0.5), each outcome in the sample space is equally likely.

Step 3: Calculate Probabilities

We need to calculate the probability of each possible value of $X$:

Step 4: Probability of 0 Boys (GGG)

There is only one outcome with 0 boys: GGG. $$P(X=0) = \frac{1}{8}$$

Step 5: Probability of 1 Boy (GGB, GBG, BGG)

There are three outcomes with 1 boy: GGB, GBG, BGG. $$P(X=1) = \frac{3}{8}$$

Step 6: Probability of 2 Boys (BBG, BGB, GBB)

There are three outcomes with 2 boys: BBG, BGB, GBB. $$P(X=2) = \frac{3}{8}$$

Step 7: Probability of 3 Boys (BBB)

There is only one outcome with 3 boys: BBB. $$P(X=3) = \frac{1}{8}$$

Step 8: Write the Probability Distribution

The probability distribution of $X$ is:

$X$ | 0 | 1 | 2 | 3 ------- | -------- | -------- | -------- | -------- $P(X)$ | 1/8 | 3/8 | 3/8 | 1/8

Final Answer: X | 0 | 1 | 2 | 3 ------- | -------- | -------- | -------- | -------- P(X) | 1/8 | 3/8 | 3/8 | 1/8

AI generated content. Review strictly for academic accuracy.

Pedagogical Audit
Bloom's Analysis: This is an APPLY question because the student needs to apply the concepts of probability and random variables to construct the probability distribution.
Knowledge Dimension: CONCEPTUAL
Justification: The question requires understanding of probability distributions and how to calculate probabilities for different outcomes of a random variable.
Syllabus Audit: In the context of CBSE Class 12, this is classified as KNOWLEDGE. The question directly relates to the syllabus content on probability distributions and random variables.

More from this Chapter

SA
A person has a fruit box that contains 6 apples and 4 oranges. He picks out a fruit three times, one after the other, after replacing the previous one in the box. Find: (i) The probability distribution of the number of oranges he draws. (ii) The expectation of the random variable (number of oranges).
SA
A survey was conducted on the patients who have undergone knee replacement surgeries. It was found that, Robotic Knee replacement surgeries have 90% success rate. On a particular day, robotic surgery was performed on three patients, A, B and C, one after the other. Assuming that the success and failure of each surgery is independent of each other, find the probability that: (i) exactly one surgery is successful, (ii) at most two surgeries are successful.
VSA
What is the probability that a customer after availing the loan will default on the loan repayment?
LA
(a) In answering a question on a multiple choice test, a student either knows the answer or guesses. Let 3/5 be the probability that he knows the answer and 2/5 be the probability that he guesses. Assuming that a student who guesses at the answer will be correct with probability 1/3. What is the probability that the student knows the answer, given that he answered it correctly? OR (b) A box contains 10 tickets, 2 of which carry a prize of ₹8 each, 5 of which carry a prize of ₹4 each, and remaining 3 carry a prize of ₹2 each. If one ticket is drawn at random, find the mean value of the prize.
MCQ_SINGLE
If \(P(A)=\frac{1}{7}\), \(P(B)=\frac{5}{7}\) and \(P(A\cap B)=\frac{4}{7},\) then \(P(\overline{A}|B)\) is:
View All Questions