The given differential equation is 2x(dy/dx) - y = 3. To find the integrating factor, we must first write the equation in the standard linear form dy/dx + P(x)y = Q(x). Dividing the entire equation by 2x, we get: $$ \frac{dy}{dx} - \frac{1}{2x}y = \frac{3}{2x} $$
Comparing the equation with the standard form, we identify P(x) = -1/(2x).
The formula for the integrating factor is IF = e^∫P(x)dx. Substituting P(x): $$ IF = e^{\int -\frac{1}{2x} dx} = e^{-\frac{1}{2} \ln|x|} $$ Using logarithmic properties a ln(b) = ln(b^a): $$ IF = e^{\ln(x^{-1/2})} = x^{-1/2} = \frac{1}{\sqrt{x}} $$
Final Answer: (B)
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