The problem asks for the area bounded by the line y = 2x - 4, the x-axis, the y-axis (x = 0), and the line x = 1. We need to calculate the definite integral of the absolute value of the function over the interval [0, 1].
The area A is given by: $$A = \int_{0}^{1} |2x - 4| \, dx$$ Since for all x in [0, 1], 2x - 4 is negative (e.g., at x=0, y=-4; at x=1, y=-2), we have |2x - 4| = -(2x - 4) = 4 - 2x.
Now, integrate the expression: $$A = \int_{0}^{1} (4 - 2x) \, dx$$ $$A = [4x - x^2]_{0}^{1}$$ $$A = (4(1) - (1)^2) - (4(0) - (0)^2)$$ $$A = 4 - 1 = 3$$
Final Answer: 3 sq. units
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