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The expression $(A+B)(A-B)$ expands to $A^2 - AB + BA - B^2$. Since matrix multiplication is generally not commutative ($AB \neq BA$), we cannot simplify $-AB + BA$ to $0$. Thus, $(A+B)(A-B) = A^2 - B^2$ is only true if $AB = BA$. It is not always true.
Matrix multiplication is not commutative in general. Therefore, $AB = BA$ is not always true for any two square matrices $A$ and $B$.
Expanding $(A+B)^2$ means $(A+B)(A+B)$. Using the distributive property: $$ (A+B)(A+B) = A(A+B) + B(A+B) = A^2 + AB + BA + B^2 $$ This is a fundamental property of matrix algebra and is always true.
The zero-product property does not hold for matrices. For example, if $A = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}$ and $B = \begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}$, then $AB = \begin{pmatrix} 0 & 0 \\ 0 & 0 \end{pmatrix}$, but neither $A$ nor $B$ is the zero matrix. Thus, this is false.
Final Answer: Only (iii)
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