Given $A = \begin{bmatrix}-p & q \\ r & p\end{bmatrix}$. We calculate $A^{2} = A \times A$:
$$A^{2} = \begin{bmatrix}-p & q \\ r & p\end{bmatrix} \begin{bmatrix}-p & q \\ r & p\end{bmatrix}$$ $$A^{2} = \begin{bmatrix}(-p)(-p) + (q)(r) & (-p)(q) + (q)(p) \\ (r)(-p) + (p)(r) & (r)(q) + (p)(p)\end{bmatrix}$$ $$A^{2} = \begin{bmatrix}p^{2} + qr & -pq + pq \\ -pr + pr & qr + p^{2}\end{bmatrix} = \begin{bmatrix}p^{2} + qr & 0 \\ 0 & p^{2} + qr\end{bmatrix}$$We are given $A^{2} = I$, where $I = \begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}$. Therefore:
$$\begin{bmatrix}p^{2} + qr & 0 \\ 0 & p^{2} + qr\end{bmatrix} = \begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}$$By comparing the corresponding elements, we get:
$$p^{2} + qr = 1$$ $$p^{2} + qr - 1 = 0$$Multiplying by -1 to match the options:
$$1 - p^{2} - qr = 0$$Final Answer: $1-p^{2}-qr=0$
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