A relation $R$ on set $A$ is reflexive if $(a, a) \in R$ for all $a \in A$. Here, $A = \{1, 2, 3\}$. For $R$ to be reflexive, it must contain $(1, 1), (2, 2),$ and $(3, 3)$. Since $(3, 3) \notin R$, the relation is not reflexive.
A relation $R$ is symmetric if $(a, b) \in R \implies (b, a) \in R$. Here, $(1, 2) \in R$, but $(2, 1) \notin R$. Therefore, the relation is not symmetric.
A relation $R$ is transitive if $(a, b) \in R$ and $(b, c) \in R \implies (a, c) \in R$. Checking the pairs: - $(1, 1)$ and $(1, 2) \implies (1, 2) \in R$ (True) - $(1, 2)$ and $(2, 2) \implies (1, 2) \in R$ (True) - $(2, 2)$ and $(2, 2) \implies (2, 2) \in R$ (True) Since all conditions hold, the relation is transitive.
Final Answer: Transitive only
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