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We are given the position vectors of two points P and Q, and we need to find the position vector of a point R on the line QP produced such that $QR = \frac{3}{2}QP$.
Since $\vec{\alpha}$ and $\vec{\beta}$ are the position vectors of P and Q respectively, we have $\vec{OP} = \vec{\alpha}$ and $\vec{OQ} = \vec{\beta}$. Therefore, $\vec{QP} = \vec{OP} - \vec{OQ} = \vec{\alpha} - \vec{\beta}$.
We are given that $QR = \frac{3}{2}QP$. Therefore, $\vec{QR} = \frac{3}{2}\vec{QP} = \frac{3}{2}(\vec{\alpha} - \vec{\beta})$.
Let $\vec{r}$ be the position vector of R. Then $\vec{OR} = \vec{OQ} + \vec{QR}$. Substituting the values we have: $$ \vec{r} = \vec{\beta} + \frac{3}{2}(\vec{\alpha} - \vec{\beta}) = \vec{\beta} + \frac{3}{2}\vec{\alpha} - \frac{3}{2}\vec{\beta} = \frac{3}{2}\vec{\alpha} - \frac{1}{2}\vec{\beta} $$ Thus, $\vec{r} = \frac{3}{2}\vec{\alpha} - \frac{1}{2}\vec{\beta}$.
Final Answer: $\frac{3}{2}\vec{\alpha} - \frac{1}{2}\vec{\beta}$
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