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Trisection means dividing the line segment into three equal parts. Let the points that trisect the wire AB be P and Q. Then AP = PQ = QB.
Since P divides AB in the ratio 1:2, we can use the section formula to find the coordinates of P. The section formula for a point dividing a line segment joining points $(x_1, y_1, z_1)$ and $(x_2, y_2, z_2)$ in the ratio m:n is given by: $P(x, y, z) = \left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}, \frac{mz_2 + nz_1}{m+n}\right)$ Here, $A(4, 1, -2)$, $B(6, 2, -3)$, $m = 1$, and $n = 2$. $P(x, y, z) = \left(\frac{1(6) + 2(4)}{1+2}, \frac{1(2) + 2(1)}{1+2}, \frac{1(-3) + 2(-2)}{1+2}\right)$ $P(x, y, z) = \left(\frac{6 + 8}{3}, \frac{2 + 2}{3}, \frac{-3 - 4}{3}\right)$ $P(x, y, z) = \left(\frac{14}{3}, \frac{4}{3}, \frac{-7}{3}\right)$
Since Q divides AB in the ratio 2:1, we can use the section formula to find the coordinates of Q. Here, $A(4, 1, -2)$, $B(6, 2, -3)$, $m = 2$, and $n = 1$. $Q(x, y, z) = \left(\frac{2(6) + 1(4)}{2+1}, \frac{2(2) + 1(1)}{2+1}, \frac{2(-3) + 1(-2)}{2+1}\right)$ $Q(x, y, z) = \left(\frac{12 + 4}{3}, \frac{4 + 1}{3}, \frac{-6 - 2}{3}\right)$ $Q(x, y, z) = \left(\frac{16}{3}, \frac{5}{3}, \frac{-8}{3}\right)$
Final Answer: The coordinates of the points are $P\left(\frac{14}{3}, \frac{4}{3}, \frac{-7}{3}\right)$ and $Q\left(\frac{16}{3}, \frac{5}{3}, \frac{-8}{3}\right)$.
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