Class JEE Chemistry ALL Q #1152
KNOWLEDGE BASED
APPLY
4 Marks 2026 JEE Main 2026 (Online) 21st January Morning Shift MCQ SINGLE
Which of the following is the correct order with respect to the property indicated?
(A) $Cl>F$ (Ionisation energy)
(B) $K_{2}O>Na_{2}O>Al_{2}O_{3}$ (Basic nature)
(C) $K>Na>Al>Mg$ (Metallic character)
(D) None of these
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Step-by-Step Solution

  1. (A) Ionization Energy: Generally, ionization energy decreases down a group. However, due to the smaller size and higher electron density of Fluorine, it experiences greater interelectronic repulsion, making it slightly easier to remove an electron from Fluorine than from Chlorine. Hence, the correct order is $F>Cl$. Therefore, option (A) is incorrect.

  2. (B) Basic Nature of Oxides: Basic nature of oxides decreases from left to right across a period and increases down a group. $K_{2}O$ is more basic than $Na_{2}O$ because K is below Na in the group. $Na_{2}O$ is more basic than $Al_{2}O_{3}$ because Na is to the left of Al in the period. Therefore, the correct order is $K_{2}O>Na_{2}O>Al_{2}O_{3}$. Hence, option (B) is correct.

  3. (C) Metallic Character: Metallic character increases down a group and decreases across a period from left to right. Therefore, the correct order is $K>Na>Mg>Al$. Hence, option (C) is incorrect.

Correct Answer: $K_{2}O>Na_{2}O>Al_{2}O_{3}$

AI Suggestion: Option B

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Pedagogical Audit
Bloom's Analysis: This is an APPLY question because it requires applying the knowledge of periodic trends to determine the correct order of properties.
Knowledge Dimension: CONCEPTUAL
Justification: The question tests the understanding of concepts related to periodic properties like ionization energy, basic nature of oxides, and metallic character.
Syllabus Audit: In the context of JEE, this is classified as KNOWLEDGE. The question directly assesses the knowledge of periodic trends and properties as covered in the syllabus.

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