Let $S=\{4,6,9\}$ and $T=\{9,10,11, \ldots, 1000\}$. If $A=\left\{a_{1}+a_{2}+\ldots+a_{k}: k \in \mathbf{N}, a_{1}, a_{2}, a_{3}, \ldots, a_{k}\right.$ $\epsilon S\}$, then the sum of all the elements in the set $T-A$ is equal to __________.

The number of elements in the set {$x \in R : (|x| - 3) |x + 4| = 6$} is equal to :

Let $R_1$ and $R_2$ be two relations defined on $R$ by $aR_1b \Leftrightarrow ab \ge 0$ and $aR_2b \Leftrightarrow a \ge b$. Then,

Let $A = \{-3, -2, -1, 0, 1, 2, 3\}$ and R be a relation on A defined by $xRy$ if and only if $2x - y \in \{0, 1\}$. Let $l$ be the number of elements in $R$. Let $m$ and $n$ be the minimum number of elements required to be added in R to make it reflexive and symmetric relations, respectively. Then $l + m + n$ is equal to:

A survey shows that $63$% of the people in a city read newspaper A whereas $76$% read newspaper B. If $x$% of the people read both the newspapers, then a possible value of x can be: