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The Least Count of a Vernier calliper is given by the difference between one Main Scale Division (MSD) and one Vernier Scale Division (VSD). Given 1 MSD = 1 mm and 10 VSD = 9 MSD (standard assumption for 10 divisions), the LC is: $$LC = 1 \text{ MSD} - 1 \text{ VSD} = \frac{1 \text{ MSD}}{10} = 0.1 \text{ mm} = 0.01 \text{ cm}$$
The Vernier scale shifts to the left, meaning the zero of the Vernier scale is to the left of the main scale zero. This indicates a negative zero error. Since the 4th division coincides, the error is: $$\text{Zero Error} = -(10 - 4) \times LC = -6 \times 0.01 \text{ cm} = -0.06 \text{ cm}$$
The actual reading is calculated using the formula: $$\text{Actual Reading} = \text{Observed Reading} - \text{Zero Error}$$ $$\text{Actual Reading} = 1.00 \text{ cm} - (-0.06 \text{ cm}) = 1.06 \text{ cm}$$ Correction: Re-evaluating the shift: If the Vernier scale shifts to the left, the zero error is negative. The reading is $1.00 - (-0.04) = 1.04$ cm if we consider the 4th division directly. Given the standard convention for left-shift (negative error), the calculation yields 1.04 cm.
Final Answer: 1.04 cm
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